Comments on: PV system technical specs http://www.catskillhouse.us/blog/pv-system-technical-specs/ Home improvement with an eye toward sustainability Tue, 15 May 2012 12:39:03 +0000 hourly 1 http://wordpress.org/?v=3.3.2 By: Paul http://www.catskillhouse.us/blog/pv-system-technical-specs/#comment-1343 Paul Wed, 22 Feb 2012 23:57:40 +0000 http://www.catskillhouse.us/blog/?p=1260#comment-1343 PJ, no worries on the name. 1 1/4 inch should work okay for two runs of #2, you should also pull a run of #6 for grounding. How big is the array? #2 seems pretty large for a solar system, unless the voltage is low and there is a lot of current, I'd opt for #6 or similar, especially for that short distance. PJ, no worries on the name. 1 1/4 inch should work okay for two runs of #2, you should also pull a run of #6 for grounding. How big is the array? #2 seems pretty large for a solar system, unless the voltage is low and there is a lot of current, I’d opt for #6 or similar, especially for that short distance.

]]> By: PJ http://www.catskillhouse.us/blog/pv-system-technical-specs/#comment-1336 PJ Wed, 22 Feb 2012 19:42:53 +0000 http://www.catskillhouse.us/blog/?p=1260#comment-1336 Paul, Sorry I called you Jason. I don't know where I got that from. Well we an update, I just got back from purchasing my 32mm (1&1/4") electrical rated PVC pipe. It wont be rendered in for a week. Paul,
Sorry I called you Jason. I don’t know where I got that from. Well we an update, I just got back from purchasing my 32mm (1&1/4″) electrical rated PVC pipe. It wont be rendered in for a week.

]]> By: PJ http://www.catskillhouse.us/blog/pv-system-technical-specs/#comment-1332 PJ Wed, 22 Feb 2012 15:17:01 +0000 http://www.catskillhouse.us/blog/?p=1260#comment-1332 Hi Jason, Neat barn. Amazing that you have done all this yourself. I am beginning a solar project where I live (remote island in the Caribbean). I'm also thinking of using electrical rated 1&1/4 inch PVC as conduit for my "panel combiner to charge controller" wire run (thankfully only 13 feet). The PVC will actually run along the back wall of my house underneath the verandah roof (no water exposure). If I keep the PVC to 1&1/4" I can hide the pipe when I render the house (the pipe will run on a corner that sticks out) so no sunlight issues and it looks neater. Here's my question. I'm thinking of using #2 AWG (1/4") for this run. Do you think I'm going to run into any issues? I'm presuming that I will only need 2 #2 AWG wires and a ground. Any thoughts much appreciated, PJ ps. NEC doesnt apply, but then again I want to make sure its safe. Hi Jason,
Neat barn. Amazing that you have done all this yourself. I am beginning a solar project where I live (remote island in the Caribbean). I’m also thinking of using electrical rated 1&1/4 inch PVC as conduit for my “panel combiner to charge controller” wire run (thankfully only 13 feet). The PVC will actually run along the back wall of my house underneath the verandah roof (no water exposure). If I keep the PVC to 1&1/4″ I can hide the pipe when I render the house (the pipe will run on a corner that sticks out) so no sunlight issues and it looks neater. Here’s my question. I’m thinking of using #2 AWG (1/4″) for this run. Do you think I’m going to run into any issues? I’m presuming that I will only need 2 #2 AWG wires and a ground.
Any thoughts much appreciated,
PJ
ps. NEC doesnt apply, but then again I want to make sure its safe.

]]> By: Cort http://www.catskillhouse.us/blog/pv-system-technical-specs/#comment-946 Cort Sat, 14 Aug 2010 01:00:56 +0000 http://www.catskillhouse.us/blog/?p=1260#comment-946 4. Calculate system temperature loss, 4.38 kW ÷ 0.88 = 4.98 kW (correct) : ) 5. Calculate system derate, 4.98 kW ÷ 0.95 = 5.24 kW (correct) : ) 6. Calculate inverter loss, 5.93 kW ÷ 0.955 = 5.26 kW (wrong) ?? (5.93 kW divided by 0.955 = 6.21 kW) ; ( Therefore, according to this, I would need a 5.26 KW DC rated PV system??? How did you get that answer? 5.26 KW DC I think you might have taken your glasses off when you did this last equation. 4. Calculate system temperature loss, 4.38 kW ÷ 0.88 = 4.98 kW (correct) : )
5. Calculate system derate, 4.98 kW ÷ 0.95 = 5.24 kW (correct) : )
6. Calculate inverter loss, 5.93 kW ÷ 0.955 = 5.26 kW (wrong) ?? (5.93 kW divided by 0.955 = 6.21 kW) ; (
Therefore, according to this, I would need a 5.26 KW DC rated PV system???
How did you get that answer? 5.26 KW DC

I think you might have taken your glasses off when you did this last equation.

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